The differentiation of `(log)_a x` (a >0) with respect to x i.e. `d/(dx)((log)_a x)= 1/(x(log)_e a)`

Explanation

To differentiate \( \log_a x \) with respect to \( x \), we can follow these steps:

### Step 1: Change of Base Formula
We start by using the change of base formula for logarithms. The change of base formula states that:
\[ \log_a x = \frac{\log_e x}{\log_e a} \]
where \( \log_e \) is the natural logarithm (often denoted as \( \ln \)).
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