y sin theta+cos^(2)theta=1

If cos theta+cos^(2)theta=1 then sin^(2)theta+2sin^(2)theta+sin^(2)theta=

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

The value of (2 (sin2 theta-2 cos^(2)theta-1))/(cos theta-sin theta-cos 3 theta +sin 3 theta)=

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

If x = (sin^(3)theta)/(cos^(2) theta)and y = (cos^(3) theta)/(sin^(2)theta) , where sin theta + cos theta = (1)/(2) , " then " x + y =

(1+ sin theta - cos theta )/( 1+ sin theta + cos theta ) + (1+ sin theta + cos theta )/( 1+ sin theta - cos theta ) =

The value of (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) is : (cos^6 theta+sin^6 theta+ 3sin^2 theta cos^2 theta)/(cosec theta sec theta(sin theta+cos theta-1)(sin theta+cos theta+1)) का मान ज्ञात कीजिए?

(xv) (cos^2 theta) / (1- tan theta) +( sin^3 theta)/ (sin theta - cos theta) = 1 + sin theta cos theta

Prove that (cos^(2) theta)/(1-tan theta)+(sin^(3) theta)/(sin theta - cos theta) =1 + sin theta cos theta .

If x= a(cos theta + sin theta ), y= a(sin theta + cos theta ), then [( d^2 y)/(d x^2 ) ] at theta = pi /4 ............. A) 0 B) 1 C) -1 D) 1/sqrt 2