`Et-Br+Ph_(3)P to Et -overset(o+)PPh_(3)(or)` `Et-Br+Ph_(3)NtoE + -overset(o+)NPh_(3)`
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The correct Answer is:
B
`EtS^(o-) ` Is more nuscleophiklic the n `EtO^(0-)` (A) `CH_(3)-CH_(2)-O^(-)gtCH_(3)-CH_(2)-OH"changed "Nu^(-)` better than neutral . more stable T.S because fo more bionding due to large size . (C ) Rate of `S_(N^(2)) alpha ["substate"][NU^(-)]` It is equal for both 1 nan d2 . (d)` ph_(3) Pgt ph_(3) n` `Et-overset(0+)P ph_(3) gt Et - overset(0+) N ph_(3) ` more stable because more change dispersion on larger atom.
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