In the reaction s given below,
`R-Cloverset((I)KCN,(II) LiAiH_(4))to" product "A`
`R-Cloverset((I) AgCN,(II) LilH_(4))to"product B"`
The compounds A andB are:

Options

A. CAHain isomers
B. Position isomers
C. Functional isomers
D. Metemaers

Explanation

To solve the problem, we need to analyze the two reactions involving R-Cl and identify the products A and B.

### Step-by-Step Solution:

1. **Identify the Reaction with KCN:**
- The first reaction involves R-Cl reacting with KCN (potassium cyanide).
- KCN dissociates into K⁺ and CN⁻. Here, CN⁻ acts as a nucleophile.

2. **Mechanism of Reaction:**
- The nucleophilic CN⁻ attacks the carbon atom of the R-Cl bond.
- This results in a substitution reaction (specifically an SN2 reaction) where the Cl atom is replaced by the CN group.
- The product formed from this reaction is an alkyl cyanide (or nitrile), which can be represented as R-CN.

3. **Reduction with LiAlH₄:**
- The alkyl cyanide (R-CN) then undergoes reduction with lithium aluminum hydride (LiAlH₄).
- LiAlH₄ is a strong reducing agent that provides H⁻ ions.
- The H⁻ ion attacks the carbon of the CN group, leading to the formation of a primary amine.

4. **Product A:**
- The product formed after reduction is a primary amine, which can be represented as R-CH₂-NH₂.
- Therefore, Product A is a primary amine.

5. **Identify the Reaction with AgCN:**
- The second reaction involves R-Cl reacting with AgCN (silver cyanide).
- In this case, AgCN also dissociates into Ag⁺ and CN⁻, but the mechanism differs.

6. **Mechanism of Reaction:**
- Here, the nitrogen atom of CN⁻ acts as the nucleophile and attacks the carbon atom of R-Cl.
- This results in the formation of an isocyanide (or carbylamine), which can be represented as R-NC.

7. **Reduction with LiAlH₄:**
- The isocyanide (R-NC) is then subjected to reduction with LiAlH₄.
- Similar to the previous reaction, the H⁻ from LiAlH₄ attacks the nitrogen atom, leading to the formation of a secondary amine.

8. **Product B:**
- The product formed after reduction is a secondary amine, which can be represented as R-CH-NH₂ (where R is connected to both carbon and nitrogen).
- Therefore, Product B is a secondary amine.

### Final Answer:
- **Product A:** R-CH₂-NH₂ (Primary amine)
- **Product B:** R-CH-NH₂ (Secondary amine)