In a certain region of space, the electric field always pointing in x - direction but its magnitude decreases from `E = 560`N/Cat `x`=0 to `E = 410`N/C at `x`=25m if a cubical box of side length I = 25 m is oriented, such that its four sides are parallel to the field lines, then charge enclosed by the box is......

A charge produce an electric field of 1 N/C at a point distant 0.1 m from it. The magnitude of charge is

In a region of space the electric field in the x -direction and proportional to x i.e., vec(E )=E_(0)xhat(i) . Consider an imaginary cubical volume of edge a with its sides parallel to the axes of coordinates. The charge inside this volume will be

The electric field due to a point charge at a distance 6 m from it is 630 N/C. The magnitude of the charge is

calculate the electric field at point (5 m, 0) due to a point charge of 1 x 10(-6) C placed at (0,5m).

Figure shows the variation of electric field intensity E versus distance x. The magnitude potential difference between the point at x = 0 to x = 6 m will be

There is uniform electric field of 8xx10^(3)hati N/C. What is the net flux (in Sl units) of the uniform electric field through a cube of side 0.3 m oriented so that its faces are parallel to the coordinate plane ?

A non-uniform electric field E=(5xhat i+3hat j)N/C goes through a cube of side length 2.0m oriented as shown. Then,

In a certain region of space, there exists a uniform and constant electric field of strength E along x-axis and uniform constant magnetic field of induction B along z-axis. A charge particle having charge q and mass m is projected with speed v parallel to x-axis from a point (a, b, 0). When the particle reaches a point 2a, b//2 , 0 its speed becomes 2v. Find the value of electric field strength of m, v and co-ordinates.

There is an electric field E in the +x -direction.If the Force on a charge 0.2C placed in this electric field is 1.0N ,what is the value of E in N/c