For the curve `7x^(2)-2y^(2)+12xy-2x+14y-22=0`, which of the following is true ?

Consider the circle x^(2) + y^(2) – 2x – 2y – 14=0 , which of following is/are true :

For the differential equation (x^2+y^2)dx-2xy dy=0 , which of the following are true. (A) solution is x^2+y^2=cx (B) x^2-y^2=cx (C) x^2-y^2=x+c (D) y(0)=0

The curve 5x^(2)+12xy-22x-19=0 is

The curve 5x^(2)+12xy-22x-12y-19=0

A curve satisfies the differential equation (dy)/(dx)=(x+1-xy^(2))/(x^(2)y-y) and passes through (0,0)(1) The equation of the curve is x^(2)+y^(2)+2x=x^(2)y^(2)(2) The equation of the is a tangent to curve (4)y=0 is a tangent to curve

Prove that the curve x^(2)+y^(2)+x+2y=0 and xy+2x-y=0 intersect orthogonally at the origin.

(i) x^(2)-7x+12=0 (ii) y^(2)+y-12=0

One of the factors of 4x^(2) + y^(2) + 14x-7y-4xy+12 is equal to