The plates of a parallel plate capacitor have surface area `A` and are initially separated by a distance `d`.They are connected to a battery of voltage `v_(0)` . Now,the plates of the capacitor are pulled apart to a separation 2d.Then increase in the energy of the battery is ..

Find out the capacitance of parallel plate capacitor of plate area A and plate separation d.

A parallel plate capacitor is charged. If the plates are pulled apart

A parallel plate capacitor has plate A and separation d between the plates. The capacitor is connected to a battery of emf V . (a) find the charge on the capacitor. (b) the plate separation is decreases to d//2 . Find the extra charge given by the battery to the positive plate. (c) work done in reducing separation between plates.

Each plate of a parallel plate capacitor has a charge q on it. The capacitor is now connected to a battery. Now,

A parallel plate air capacitor is connected to a battery. If plates of the capacitor are pulled farther apart, then which of the following statements is/are correct ?

A parallel plate air capacitor is made using two square plates each of side 0.2 m, spaced 1 cm apart. It is connected to a 50V battery. If the battery is disconnected and then the plates are pulled apart to a separation of 2 cm, what are the answers to the above parts ? S

The plates of a parallel-plate capacitor are separated by a solid dielectric. This capacitor and a resistor are connected in series across the terminals ofa battery. Now the plates of the capacitor are pulled slightly further apart. After some time circuit again attains steady state.

A parallel plate capacitor has plates of area 4 m^2 separated by distance of 0.5 mm. The capacitor is connected across a cell of emf 100 V. Find the capacitance, charge and energy stored in the capacitor.