A charge `q` is placed in the middle of a line joining the two equal and like point charge `Q` .This charge q will remain in equilibrium if `q=(Q)/(x)` .What is `x`?

A charge q is placed at the centre of the line joining two equal charges Q. The system of the three charges will be in equilibrium if q is equal to:

If a charge q is placed at the centre of the line joining two equal charges Q such that the system is in equilibrium then the value of q is

A charge Q is placed at the centre of the line joining two point charges +q and +q as shown in figure. The ratio of charges Q and q is

Two point charges q_(1) = +2 C and q_(2) = - 1C are separated by a distance d . The position on the line joining the two charges where a third charge q = + 1 C will be in equilibrium is at a distance

A point charge q is placed at the centre of a line joining two equal charges Q. The whole system is in the state of equilibrium. Can you impose some lower limit on the magnitude of the charge Q?

Two equal charges, +Q each, are at a distance r from each other. A third charge is placed on the line joining the above two charges such that all these charges are in equilibrium. Find q, in terms of Q.

Two idential point charges Q are kept at a distance r from each other. A third point charge is placed on the line joing the above two charges such that all the three charges are in equilibrium. The third charge (a) should be of magnitude q=……….. (b) should be of sign ....... (c ) should be placed ........ .