A parabola with focus `S (1,2)` touches both the axes then the equation to directrix is a.)`2x+y=0` b.)`2x-y=0` c.)`x+2y=0` d.)`x-2y=0`

The focal chord of the parabola y^(2)=ax is 2x-y-8=0. Then find the equation of the directrix.

Equation of parabola with focus (0,2) and directrix y + 2 = 0 is

The parametric equations of a parabola are x=t^(2)+1,y=2t+1. The Cartesian equation of its directrix is x=0 b.x+1=0 c.y=0 d.none of these

Let parabolas y=x(c-x) and y=x^(2)+ax+b touch each other at the point (1,0) then b-c=

Equation of the directrix of the parabola y^(2)+4x+2=0 is

The equation of the parabola whose focus is (1,-1) and the directrix is x+y+7=0 is x^(2)+y^(2)-2xy-18x-10y=0x^(2)+y^(2)-18x-10y-45=0x^(2)-18x-10y-45=0x^(2)+y^(2)-2xy-18x-10y-4=0

Let the parabolas y=x(c-x)and y=x^(2)+ax+b touch each other at the point (1,0), then-

. If 2x^(2)-5xy+2y^(2)=0 represents two sides of triangle whose centroid is (1,1) then the equation of the third side is (A)x+y-3=0 (B) x-y-3=0 (C) x+y+3=0 (D) x-y+3=0

Find the equation of the parabola whose: focus is (0,0) and the directrix 2x-y-1=0

x=2,y=-1 is a solution of the linear equation x+2y=0 (b) x+2y=42x+y=0 (d) 2x+y=5