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If (alpha-beta)=(pi)/(2) ,then the chord...

If `(alpha-beta)=(pi)/(2)` ,then the chord joining the points whose eccentric angles are `alpha` and `beta` of the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1` touches the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=(1)/(k)`, then (`5k^(2)+2)` is equal to

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