`I=int(1)/(3x^(2)+6)dx`

I=int(1)/(x^(3)+x^(2)+x+1)dx

Evaluate I=int 1/(3x^2+4x+6)dx

int(1)/((6-3x))dx

l_(1)=int_(0)^(1)3^(x^(2))dx,l_(2)=int_(0)^(1)3^(x^(3))dx,l_(3)=int_(1)^(2)3^(x^(2))dx,l_(4)=int_(1)^(2)3^(x^(3))dx then (i)I_(1)>I_(2)(ii)I_(2)>I_(1)(iii)I_(3)>I_(4)(iv)I_(4)>I_(3)

Evaluate: (i) (x^(2)+3x-1)/((x+1)^(2))dx (ii) int(2x-1)/((x-1)^(2))dx

Evaluate : (i) int(3x+5)^7dx (ii) int(4-9x)^(5)dx (iii) int(1)/((2-3x)^(4))dx (iv) intsqrt(ax+b)\ dx

int_(1)^(6)(3x-2)dx

int(6)/((1-2x)^(3))dx

int (3x^2+6) dx

Evaluate: (i) int(x^(2)+x+5)/(3x+2)dx (ii) int(2x+3)/((x-1)^(2))dx