If `sin theta+cos theta=a,tan theta+cot theta=b,` show that `(a^(2)-1)/(2)=(1)/(b)`

If sin theta+cos theta=a and tan theta+cot theta=b, then b(a^(2)-1) =

sin theta+cos theta=a" and "tan theta+cot theta=b," then "^(b(a^(2)-1))=

"If "sin theta+cos theta=a" and "tan theta+cot theta=b," then "b(a^(2)-1)=

If sin theta+cos theta=a" and "tan theta+cot theta=b," then "^(b(a^(2)-1)=

If tan theta+cot theta=2 then sin theta+cos theta=

If tan theta-cot theta=alpha and sin theta+cos theta=b then (b^(2)-1)^(2)(a^(2)+4) is

tan theta-cot theta=a and sin theta+cos theta=b(b^(2)-1)^(2)(a^(2)+4)

If tan theta-cot theta=a and sin theta+cos theta=b ,then (b^(2)-1)^(2) . (a^(2)+4)=

(sin theta" cosec "theta tan theta cot theta)/(sin^(2)theta+cos^(2)theta)

If tan theta=(a)/(b), show that (a sin theta-b cos theta)/(a sin theta+b cos theta)=(a^(2)-b^(2))/(a^(2)+b^(2))