The value of u so that the ball reaches at point A (g = 10m/s2) A u 45° 20m 10m -15m->

A ball is dropped onto a step at a point P and rebounds with velocity u_@ at an angle of 45^@ with the vertical. The value of u_0 knowing that just before the ball hits the point Q its velocity forms an angle 30^@ with the vertical is: (g=10m//s^2)

A boy throws a ball upward with velocity v_(0)=20m//s . The wind imparts a horizontal acceleration of 4m//s^(2) to the left. The angle theta at which the ball must be thrown so that the ball returns to the boy's hand is : (g=10ms^(-2))

A ball of mass 400 gm is dropped from a height of 5 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100 newton so that it attains a vertical velocity of 20 m/s. The time for which the ball remains in contact with the bat is (g=10m//s^(2))

A ball of mass 50 g is dropped from a height of 20 m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 200 N, so that it attains a vertical height of 45 m. The time for which the ball remains in contact with the bat is [Take g=10m//s^(2)]

A ball of the mass 400gm is dropped from a height of 5m. A boy on the ground hits the ball vertically upwards with a bat with an average force of 100N so that it attains a vertical height of 20m. The time for which the ball remains in contect with the bat is [ g=10m//s^(-2)]

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

A ball falls of a table and reaches the ground in 10 s. Assuming g=10m//s^(2) , calculate its speed on reaching the ground and the height of the table.

A ball is throw vertically upward. It has a speed of 10 m//s when it has reached on half of its maximum height. How high does the ball rise ? (Taking g = 10 m//s^2 ).