If `5x-y,2x+y,x+2y` are in A.Pand `(x-1)^(2),xy+1,(y+1)^(2)` are in G.P `(x!=0)` then `x+y=`

If 5x-y,2x+y,x+2y are in "A.P" and (x-1)^(2),xy+1,(y+1)^(2) are in G.P (x!=0) then x+y=

The complex numbrs x and y such that x,x+2y,2x+y are n A.P. and (y+1)^2, xy+5, (x+1)^2 are in G.P. are (A) x=3, y=1 (B) x=-1+2sqrt(2)i, y=1/3 (-1+2sqrt(2)i) (C) x=sqrt(2)+i, y=3sqrt(5)-sqrt(2)i (D) x=-1(1+2sqrt(2)i), y= - 1/3 (1+2sqrt(2)i)

Three distinct points A(x_(1),y_(1)),B(x_(2),y_(2)),C(x_(3),y_(3)) lie on the parabola y=3x^(2). If x_(1),x_(2),x_(3) are in A.P.and y_(1),y_(2) and y_(3) are in G.P.then the common ratio of the GP is

If x_(1),x_(2),x_(3), are in A.P.and y_(1),y_(2),y_(3), are also in A.P.with same common difference then the points (x_(1),y_(1)),(x_(2),y_(2)) and (x_(3),y_(3)) form

If (dy)/dx = (xy)/(x^2 + y^2), y(1) = 1 and y(x) = e then x =

If 5x^(2) -4xy +y^(2) -2x +1=0 then value of x+y is

(xy)/(x-y)=(1)/(2);(xy)/(x+y)=(1)/(5) wherex +y!=0;x-y!=0

If 5x^(2) + 4xy + y^(2) + 2x + 1= 0 then find the value of x, y

If x:y::5:2, then (x ^(2) - xy + y ^(2))/( x ^(2) + xy + y ^(2)) = ?