The particles position as a function of time is given as `x=t^(3)-3t^(2)+6,` then maximum value of `x` occurs when "t=

The particle's position as a funciton of time is given as x=5t^2-9t+3 . Find out the maximum value of position co-ordinate? Also, plot the graph.

Particle 's position as a function of time is given by x=-t^(2)+4t+4 find the maximum value of position coordinate of particle.

A particle is moving in a straight line. The variation of position ‘x’ as a function of time ‘t’ is given as x = (t^3 – 6t^2 20t 15) m. The velocity of the body when its acceleration becomes zero is :

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A particle's position as a function of time is described as y (t) = 2t^(2) + 3t + 4 . What is the average velocity of the particle from t = 0 to t = 3 sec ?

A foce acts on a 30.g particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where x is in metre and t in second. The work done during the first 4s is

A force act on a 30 gm particle in such a way that the position of the particle as a function of time is given by x = 3 t - 4 t^(2) + t^(3) , where x is in metros and t is in seconds. The work done during the first 4 second is

The position of a particle moving in a string line is given by x = 3t^(3) - 18 t^(2) + 36 t Here, x is in m and t in second . Then