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(sintheta)/(1+costheta) is equal to (1+c...

`(sintheta)/(1+costheta)` is equal to `(1+costheta)/(sintheta)` (b) `(1-costheta)/(costheta)` (c) `(1-costheta)/(sintheta)` (d) `(1-sintheta)/(costheta)`

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