Sound heard by an observer is given by an equation as Y=10sin2 πt cos6πt at x=0, Beat frequency is

There is a source of sound (a tuning fork) moving towards a reflecting wall will a speed of 30 ms^(-1) . The velocity of the sound in air is 330 ms^(-1) and the frequency of the tuning fork is 600 Hz. The observer is between the source and the wall and is moving with some velocity V_(1) towards the wall. The beat frequency heard by the observer is 4 Hz. If the tuning fork is waxed, the frequency beats heard by the observer becomes 3 Hz. If the new frequency of tuning fork is k then k//50 is

A source of sound of frequency 90 vibrations/ sec is approaching a stationary observer with a speed equal to 1/10 the speed of sound. What will be the frequency heard by the observer

A source of sound emitting a note of frequency 90 Hz moves towards an observer with speed equal to ( (1)/( 10 ) )^(th ) of velocity of sound.The frequency of the note heard by the observer will be

A source of frequency 1 kHz is moving towards a stationary observer with velocity of 0.9 times that of sound. What is the frequency heard by the observer ?

The equation 3sin^(2)x+10cos x-6=0 is satisfied,if

If a source emitting waves of frequency f moves towards an observer with a velocity (v)/(4) and the observer moves away from the source with a velocity (v)/(6) , the apparent frequency as heard by the observer will be (v=velocity of sound)

The source producing sound and an observer both are moving along the direction of propagation of sound waves. If the respective velocities of sound, source and an observer are v, v_(s) and v_(0) , then the apparent frequency heard by the observer will be (n = frequency of sound)

An aeroplane of frequency 2f is moving towards a stationary observer. Frequency heard by observer is 4f then find out ratio of speed of aeroplane and sound