If `C_(0)+C_(1)+C_(2)+......+C_(n)=128` then `C_(0)-(C_(1))/(2)+(C_(2))/(3)-(C_(3))/(4)+.....=`

C_(0)+(C_(1))/(2)+(C_(2))/(3)+...+(C_(n))/(n+1)=

If (1+x)^(n)=C_(0)+C_(1)x+C_(2)x^(2)+...+C_(n)x^(n) then 2C_(0)+(C_(1))/(2)+2^(3)(C_(2))/(3)+...+2^(n+1)(C_(n))/(n+1)=

If C_(0), C_(1), C_(2),..., C_(n) are binomial coefficients in the expansion of (1 + x)^(n), then the value of C_(0) - (C_(1))/(2) + (C_(2))/(3) - (C_(3))/(4) +...+ (-1)^(n) (C_(n))/(n+1) is

(C_(0))/(1)+(C_(1))/(2)+(C_(2))/(3)+.........(C_(n))/(n+1)=

If (1+x)^(n)=C_(0)+C_(1)x+C_(2)x^(2)+...+C_(n)x^(n) then for n odd ,C_(0)^(2)-C_(1)^(2)+C_(2)^(2)-C_(3)^(2)+...+(-1)C_(n)^(2), is equal to

If (1+x)^(n)=C_(0)+C_(1)x+…..+C_(n)x^(n) , then (C_(1))/(C_(0))+(2C_(2))/(C_(1))+(3C_(3))/(C_(2))+....+(nC_(n))/(C_(n-1)) is :

Prove that (i) C_(1)+2C_(2)+3C_(3)+……+nC_(n)=n.2^(n+1) (ii) C_(0)+(C_(1)/(2)+(C_(2))/(3)+….+(C_(n))/(n+1)=(2^(n+1)-1)/(n+1)

If C_(0),C_(1),C_(2),...,C_(n) denote the binomial coefficientsin the expansion of (1+x)^(n), then (C_(0))/(2)-(C_(1))/(3)+(C_(2))/(4)-(C_(3))/(5)+......+(-1)^(n)(C_(n))/(n+2)=