The equation of the chord of the ellipse `2x^(2)+3y^(2)=6` having `(1,-1)` as its mid point is

The equation of the chord of the ellipse x^(2) + 4y^(2) = 4 having the middle point at (-2, (1)/(2)) is

The equation of the chord of the ellipse 2x^(2)+5y^(2)=20 which is bisected at the point (2,1) is

The length of the chord of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 ,whose mid point is (1,(2)/(5)) ,is equal to :

The equation of the chord of x^(2)+y^(2)-4x+6y+3=0 whose mid point is (1,-2) is

Equation of the chord of the circle x^(2) + y^(2) - 4x = 0 whose mid-point is (1,0) , is

Find the length of the chord of the ellipse (x^(2))/(25)+(y^(2))/(16)=1, whose middle point is ((1)/(2),(2)/(5))

If the equation of chord ofthe ellipse " (x^(2))/(25)+(y^(2))/(16)=1 " joining "],[" the two points " P((pi)/(3)) " and Q((pi)/(6)) " on it is " (x)/(lambda_(1)) + (y)/(lambda_(2)) = (sqrt(3)+1)/(2) ],[" then " 20 lambda_(1) + 25 lambda_(2) ="