Home
Class 12
MATHS
The number of ways of arranging "11" obj...

The number of ways of arranging "11" objects "A,B,C,D,E,F,`alpha,alpha,alpha,beta,beta` so that every `beta` lies between two `alpha` (not necessarily adjacent) is `K times 6!times^(11)C_(5)` ,then "K" is (For e.g.here the arrangement "`A alpha B alpha C beta E beta alpha FD` is valid but "`A alpha B alpha C beta E alpha F beta D"` is not "

Promotional Banner

Similar Questions

Explore conceptually related problems

| alpha alpha1 beta F|=(alpha-P)(beta-alpha)

Eleven objects A, B, C, D, E, F, alpha, alpha, alpha, beta and beta are arranged in a row, then the probability that every beta has two alpha as neighbors is

Statement 1:alpha^(beta)>beta^(alpha), FOR 2.91 e

If alpha, beta are the zeros of kx^(2)-2x+3k such that alpha+beta = alpha beta then k = ?

If alpha,beta are the roots of ax^(2)+bx+c-0 then alpha beta^(2)+alpha^(2)beta+alpha beta=

If alpha. beta are roots of the equation ax^(2)+bx+c=0 and alpha-beta=alpha*beta then