6x^(2)+5ax-6a^(2)

6x^(2)+5x-6

The area of the square formed by thelines 6x^(2)-5xy-6y^(2)=0 and 6x^(2)-5xy-6y^(2)+x+5y-1=0 in sq.units is

If the pair of lines 6x^(2)-5xy-6y^(2)=0, 6x^(2)-5xy-6y^(2)+x+5y-1=0 form a square then area of square is

Factories: x ^(2) +6ax+9a ^(2)

Find the square root of (6x^(2) + 5x - 6) (6x^(2) - x - 2) (4x^(2) + 8x + 3)

(2x ^(2) + 3x -4) (3x +2) = 6x ^(3) + ax ^(2) -6x-8 In the above equation, a is a constant. If the equation is true for all value of x, what is the value of a ?

The four lines 6x^(2) – 5xy - 6y^(2) + x+5y–1=0  and 6x^(2) – 5xy -6y^(2) = 0 , form a

Factorise: 6x ^(2) - 5x -6