The differentiation of `a^x(a >0,a!=1)` with respect to `x` is `a^x(log)_e adot` i.e. `d/(dx)(a^x)=a^x(log)_e a`

Explanation

as we know that he differentiation of `a^x(a >0,a!=1)`
with respect to `x` is `a^x(log)_e adot` is


i.e. `d/(dx)(a^x)=a^x(log)_e a`

so it is true.