(ii)t^(2)-15

Find the zeros of polynomial h(t)=t^(2)-15 and verify the relationship between the zeros and their coefficients:

If displacement S at time t is S=t^(3)-3t^(2)-15t+12 , then acceleration at time t=1 sec is

Find the zeroes of the following polynomials by factorisation method and verify the relations between the zeroes and the coefficients of the polynomials (iv) t^(3)-2t^(2)-15t .

Find the zeroes of the following polynomials by factorisation method and verify the relations between the zeroes and the coefficients of the polynomials (iv) t^(3)-2t^(2)-15t .

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. (v) t^(2) - 15

The distances moved by a particle in time t seconds is given by s=t^(3)-6t^(2)-15t+12 . The velocity of the particle when acceleration becomes zero, is

The distances moved by a particle in time t seconds is given by s=t^(3)-6t^(2)-15t+12 . The velocity of the particle when acceleration becomes zero, is

If a particle moves is a straight line according to s=t^(3)-6t^(2)-15t , the time interval during which the velocity is negative and acceleration is positive is

The position of a particle moving along a straight line is defined by the relation, x=t^(3)-6t^(2)-15t+40 where x is in meters and t in seconds.The distance travelled by the particle from t=0 to t=2 s is?

If S=2t^(3)-3t^(2)+15t-8 ,then the initial velocity is