If `((1+i)/(1-i))^2=x+i y ,` find`x+ydot`

Explanation

To solve the problem \(\left(\frac{1+i}{1-i}\right)^2 = x + iy\) and find \(x + y\), we can follow these steps:

### Step 1: Simplify the fraction \(\frac{1+i}{1-i}\)

To simplify \(\frac{1+i}{1-i}\), we multiply the numerator and denominator by the conjugate of the denominator, which is \(1+i\):

\[
\frac{1+i}{1-i} \cdot \frac{1+i}{1+i} = \frac{(1+i)(1+i)}{(1-i)(1+i)}
...