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If (1+i)z=(1-i) z , then show that z=-...

If `(1+i)z=(1-i) z ` , then show that `z=-i z dot`

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We have,`(1+i)z=(1−i)z'`
`z/(z')​=[(1−i)(1-i)]/[(1+i)​(1−i)]=(1−2i+i^2)/(1-i^2)​=−i`
`z=-iz'`
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