If 3x + 2y - 6 = 0 is written in normal form then `alpha` is equal to:

If the equation 3x + 3y + 5 = 0 is written in the form x cos alpha + y sin alpha = p , then the value of sin alpha + cos alpha is

If the equation 3x + 3y + 5=0 is written in the form x cos alpha + y sin alpha = p , then the value of sin alpha + cos alpha is a) sqrt2 b) (1)/( sqrt2) c) - sqrt2 d) - (1)/( sqrt2)

Reduce x+sqrt(3y) - 4 = 0 to the : (iii) Normal form and find the values of p and alpha

If (alpha,beta) is the centre of the circle which touches the curve x^(2)+xy-y^(2)=4 at (2,2) and the line 3x-y+6=0 ,then the value of alpha+beta is equal to

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Reduce x+sqrt(3y) + 4 = 0 to the : (iii) Normal form and find the values of p and alpha

Let A=[(x,2y),(-1,y)], x , y in R If AA'= [(1,0),(0,alpha)] (alpha in R) , then alpha+y^2 is equal to :