If `y_1, y_2, y_3` be the ordinates of a vertices of the triangle inscribed in a parabola `y^2=4a x ,` then show that the area of the triangle is `1/(8a)|(y_1-y_2)(y_2-y_3)(y_3-y_1)|dot`

Explanation

To solve the problem, we need to find the area of a triangle inscribed in the parabola \( y^2 = 4ax \) with vertices at points whose ordinates are \( y_1, y_2, y_3 \). The abscissas corresponding to these ordinates can be derived from the equation of the parabola.

### Step-by-Step Solution:

1. **Identify the coordinates of the vertices of the triangle:**
The vertices of the triangle can be represented as:
\[
A(x_1, y_1), \quad B(x_2, y_2), \quad C(x_3, y_3)
...