Find the vertex, focus, directrix, axis and latus-rectum of the parabola `y^2=4x+4ydot`

Explanation

Given equation

`4x^2+y`=o

`=>-y/4`=`x^2`

On comparing the given equation with

`x^2`=-4ay

4a=`1/4``=>a=1/6`

`:. `Vertex =(0,0)=

Focus =(0,a)=`(0,-1/16)`
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