" 9) "n^(3)+y^(3)+2x^(2)-2y^(2)

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

The HCF of x^(2) - y^(2), x^(3) - y^(3), …... x^(n) - y^(n) , where n in N is ………. .

(x+y)^(3)-(x-y)^(3) can be factorized as 2y(3x^(2)+y^(2)) (b) 2x(3x^(2)+y^(2))2y(3y^(2)+x^(2)) (d) 2x(x^(2)+3y^(2))

((x +y)^(3) + (x-y)^(3))/(2) -y (3x^(2) + y^(2)) = ______

x^(3)-3xy^(2)=183x^(2)y-y^(3)=26 If x,y in N

Find the sum of x(x+y) + x^(2) (x^(2) + y^(2)) + x^(3) (x^(3) + y^(3))+ ……..to n terms

The HCF of (x^(3)y)/(m^(2)n^(4)), (x^(2)y^(3))/(m^(2)n^(2)) and (x^(4)y^(2))/(mn^(3)) is