[2x+y=6],[6x+3y=20]

2x + y = 6, 6x + 3y = 18 .

Solve: {:(2x + y = 2),(6x - 3y = 20):}

2x-y=1 ; 6x+3y=5

Solve the following by Cramer's rule : 2x-3y=5, 4y+5z=6, 6x+7z=20

4x-2y=3 6x-3y=5

2x+3y=5 6x+9y=10

6x-4y=-12,8x-3y=-2

The lines x-y-6=0, 4x-3y-20=0 and 6x+5y+8=0 are:

The midpoint of a chord of the ellipse x^(2)+4y^(2)-2x+20y=0 is (2,-4) .The equation of the chord is (A) x-6y=26 (B) x+6y=26(C)6x-y=26(D)6x+y=26