+9b^(2))quad " (ii) "(m+(n)/(7))^(3)(m-(n)/(7))

Simplify each of the products: (m+(n)/(7))^(3)(m-(n)/(7))

If (7m+2n)/(7m-2n)=5/(3) use properties of proportion to find (i) m:n (ii) (m^(2)+n^(2))/(m^(2)-n^(2))

Show that: :(3x+7)^(2)-84x=(3x-7)^(2)(9a-5b)^(2)+180ab=(9a+5b)^(2)((4m)/(3)-(3n)/(4))^(2)+2mn=(16m^(2))/(9)+(9n^(2))/(16)

Find m, if ((3)/(7))^(9)div((3)/(7))^(5)=((3)/(7))^((3m+2)/(m-2))

If (1)/(3)log_(3)M+3log_(3)N=1+log_(0.008)5, then M^(9)(9)/(N) b.N^(9)=(9)/(M) c.M^(3)=(3)/(N) d.N^(9)=(3)/(M)

Find m , if (3/7)^9 / (3/7)^5 = (3/7)^((3m + 2)/(m - 2))

If (4m + 3n)/(4m - 3n) = (7)/(4) use properties of proportion to find : (i) m : n (ii) (2m^(2) - 11n^(2))/(2m^(2) + 11n^(2)) .

If (1)/(3)log_(3)M+3log_(3)N=1+log_(0.008)5, then M^(9)=(9)/(N)(b)N^(9)=(9)/(M)M^(3)=(3)/(N)(d)N^(9)=(3)/(M)

Show that : (3x+7)^2-84 x=(3x-7)^2 (9a-5b)^2+180 a b=(9a+5b)^2 ((4m)/3-(3n)/4)^2+2m n=(16 m^2)/9+(9n^2)/(16)

If a+b=1,a^(2)+b^(2)=2 and given that a^(7)+b^7=(m)/(n) where m & n are co-primes. Find m+n