If `x_n`=cos`pi/(2^n)`+isin`pi/(2^n)` , prove that `x_1x_2x_3 x_oo=-1.`

Explanation

To prove that \( x_1 x_2 x_3 \cdots x_\infty = -1 \) where \( x_n = \cos\left(\frac{\pi}{2^n}\right) + i \sin\left(\frac{\pi}{2^n}\right) \), we can rewrite \( x_n \) in exponential form using Euler's formula:

### Step 1: Rewrite \( x_n \)
Using Euler's formula, we have:
\[ x_n = e^{i \frac{\pi}{2^n}} \]

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