Let `f(x)=x^2+ 1/x^2` and `g(x)=x-1/x, x in R-{-1,0,1}`. If `h(x) = f(x)/g(x)` then the local minimum value of `h(x)` is: (1) 3 (2) `-3` (3) `-2sqrt(2)` (4) `2sqrt(2)`