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log(1+x)^((1+x))...

log(1+x)^((1+x))

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If y=(x-1)log(x-1)-(x+1)log(x+1), prove : (dy)/(dx)=log((x-1)/(1+x))

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int ln(1+x)^(1+x)dx

If y=log[(x-1)^(x-1)]-log[(x+1)^(x+1)]," then: "(dy)/(dx)=

int((ln((1+x)/(1-x)))/(1-x^(2))dx