" 4."pi" is "

If f(x) = {((1-sqrt2sinx)/(pi-4x), x ne pi/4),(a, x = pi/4):} is continuous at pi/4 , then a =

pi/4 + pi - pi/3 - pi/6

cos^(4) ""(pi)/(12) - sin^(4)"" (pi)/(12) is equal to

The area bounded by x^2+y^2-2x=0a n dy=sinpi/2x in the upper half of the circle is pi/2-4/pi 2. pi/4-2/pi 3. pi-8/pi 4. pi+8/pi 5. pi/2+4/pi

cos ^ (4) ((pi) / (8)) + cos ^ (4) ((3 pi) / (8)) + cos ^ (4) ((5 pi) / (8)) + cos ^ ( 4) ((7 pi) / (8)) =