`|1+costheta+isintheta|=?`

If z=1-costheta+ isintheta , then |z| is equal to:

Assertion (A) : (Costheta+iSintheta)^(10)+(Costheta-iSintheta)^(10)=2cos10theta Reason (R) : (1+costheta+isintheta)^n+(1+costheta-isintheta)^n= 2^(n+1)cos^n(theta/2)cos((ntheta)/(2))

Select and write the correct answer from the given alternatives in each of the following: Let z = (costheta + isintheta) / (costheta - isintheta) , pi / 4 < theta < pi / 2 . Then, arg z is

(1-costheta+isintheta)^8 =

(1-costheta+isintheta)^6 =

The amplitude of 1+costheta+isintheta is

(1+costheta-isintheta)^4 =

The conjugate of costheta-isintheta is

If theta is real then the modulus of 1/(1+costheta+isintheta) is

Convert the complex number Z in a+ib form if Z=1/(1-costheta-isintheta)