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[(1+cos(pi/8)+isin(pi/8))/(1+cos(pi/8)-s...

`[(1+cos(pi/8)+isin(pi/8))/(1+cos(pi/8)-sin(pi/8))]^8=?`

Answer

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The expression [(1+sin(pi/8)+icos(pi/8))/(1+sin(pi/8)-icos(pi/8))]^8 is equal is

((1+"cos"(pi)/(8)+"isin"(pi)/(8))/(1+"cos"(pi)/(8)-"isin"(pi)/(8)))^(8)=

Knowledge Check

  • The value of [(1+cos(pi/8)+isin(pi/8))/(1+cos(pi/8)-isin(pi/8))]^8 is

    A
    0
    B
    i
    C
    1
    D
    -1

  • ((1+cos. pi/8+isin. pi/8)/(1+cos. pi/8- isin. pi/8))^(8)=

    A
    `1 + i`
    B
    1
    C
    `1- i`
    D
    -1

  • ((1+cos""(pi)/(8)-isin""(pi)/(8))/(1+cos""(pi)/(8)+isin""(pi)/(8)))^(8) is equal to

    A
    1
    B
    -1
    C
    2
    D
    `(1)/(2)`

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    Explore conceptually related problems

    ((1+cos""(pi)/(8)-isin""(pi)/(8))/(1+cos""(pi)/(8)+isin""(pi)/(8)))^(8)

    Evaluate: (1+cos(pi/8))(1+cos(3pi/8))(1+cos(5pi/8))(1+cos (7pi/8))

    Find the value of (1+cos (pi/8))(1+cos(3pi/8))(1+cos(5pi/8))(1+cos(7pi/8))

    [(1+sin(pi//8)+icos(pi//8))/(1+sin(pi//8)-icospi//8)]^(-8//3)

    ((1 + "cos"(pi)/(8) -i "sin"(pi)/(8))/(1 + "cos"(pi)/(8) + i "sin" (pi)/(8)))^(12)=

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