" (3) Arcturize (i) "x^(8)-y^(8)

Factorise : x^(8)-y^(8)

Factorise x^(8)-y^(8)

Factorizing the difference of squares: (i)x^(8)-y^(8)(ii)a^(12)x^(4)-a^(4)x^(12)

The HCF of (x^(4) - y^(4)) and (x^(8) - y^(8)) is:

Factorise the following expression: (i) 8x^(3) +125y^(3) (ii) 27x^(3) -8y^(3) (iii) a^(6) -64

Factorize following experessios (i) 8x^(3)-27y^(3)" (ii)"8x^3-125y^3+2x-5y

Factorize following experessios (i) 8x^(3)-27y^(3)" (ii)"8x^3-125y^3+2x-5y

Factorize following experessios (i) 8x^(3)-27y^(3)" (ii)"8x^3-125y^3+2x-5y

Given (x^(2)+y^(2))/(x^(2)-y^(2))+(x^(2)-y^(2))/(x^(2)+y^(2))=k then (x^(8)+y^(8))/(x^(8)-y^(8)) in terms of k is equal to