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If `alpha,beta` are roots of the equation `x^2+3x+7=0,t h e n 1/alpha+1/beta` is equal to (a) `7//3` (b) `-7//3` (c) `3//7` (d) `-3//7`

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Given `alpha,beta `are roots of the equation `x^2+3x+7=0`
we can see from given quadratic equation,
`alpha+beta=−3​ and alphabeta=7`​
so,
`1/alpha+1/beta=(alpha+beta)/(alphabeta)`
=`-3/7`
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