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The number of solution of x^2+|x-1|=1 i...

The number of solution of `x^2+|x-1|=1` is (a) `0` (b) `1` (c) `2` (d) `3`

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To solve the equation \( x^2 + |x - 1| = 1 \), we will consider two cases based on the definition of the absolute value. ### Step 1: Case 1 - \( x \geq 1 \) In this case, \( |x - 1| = x - 1 \). Therefore, the equation becomes: \[ x^2 + (x - 1) = 1 \] Simplifying this, we have: ...
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Knowledge Check

  • The number of solutions of sqrt(3x^(2)+x+5)=x-3 is (A) 0 (B) 1 (C) 2 (D) 4

    A
    `0`
    B
    `1`
    C
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    D
    `4`

  • The number of real solutions of |2x-x^(2)-3|=1 is 0(b)2(c)3(d)4

    A
    `0`
    B
    `2`
    C
    `3`
    D
    `4`

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