Solve the quadratic equations`` by using the general expressions for the roots of a quadratic equation: `x^2-(3sqrt(2)-2i)x-6sqrt(2)i=0`

Explanation

Given,`x^2-(3sqrt(2)-2i)x-6sqrt(2)i=0`

Let `x=a+ib`

,`(a+ib)^2-(3sqrt(2)-2i)(a+ib)-6sqrt(2)i=0`

=`(a^2−b^2−3sqrt(2)
​a+2b)+i(−2a+2ab+6sqrt(2)
​−3sqrt(2)
​b)=0+0i`

Compairing both sides we get

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