Write the number of real roots of the equation `(x-1)^2+(x+2)^2+(x-3)^2=0.`

Explanation

Given,`(x-1)^2+(x+2)^2+(x-3)^2=0.`

`x^2−2x+1+x^2+4x+4+x^2−6x+9=0`


⇒`3x^2−4x+14=0`


Let D be the discriminant of the obtained quadratic equation.
`

D=(−4)^2−4×14×3=16−168=−152`

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