Solve: `x^2-(7-i)x+(18-i)=0`

Explanation

`x^2 - (7-i)x - (18-i) = 0`

This is a quadratic equation and its roots can be given as,

`x = (-b+-sqrt(b^2-4ac))/(2a)`

Here, `a = 1, b = -(7-i), c= (18-i)`

Now, `b^2-4ac = (-(7-i))^2 - 4(18-i)`

`= 49+i^2 - 14i -72+4i`...[As `i^2 = -1`]

`= 49-1 - 14i -72+4i`

`=-24-10i`

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