If `alpha,beta` are roots of the equation `x^2-p(x+1)-c=0,` then write the value of `(1+alpha)(1+beta)dot`

Explanation

Given `alpha and beta` are roots of quadratic equation

`f(x)=x^2−p(x+1)−c=x^2−px−p−c=x^2−px−(p+c)`


Comparing with `ax^2+bx+c`

we have, `a=1, b=−p and c=−(p+c)`

now sum of roots

`alpha+beta=−b/a=−(−p)​=p`
and
product of roots

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