If `alpha,beta` are the roots of the equation `x^2+p x+q=0,t h e n-1/alpha,-1/beta` are the roots of the equation `x^2-p x+q=0` (b) `x^2+p x+q=0` (c) `q x^2+p x+1=0` (d) `q^2-p x+1=0`

Explanation

To solve the problem, we need to find the new quadratic equation whose roots are \(-\frac{1}{\alpha}\) and \(-\frac{1}{\beta}\), given that \(\alpha\) and \(\beta\) are the roots of the equation \(x^2 + px + q = 0\).

### Step-by-Step Solution:

1. **Identify the original roots and their properties**:
- The roots of the original equation \(x^2 + px + q = 0\) are \(\alpha\) and \(\beta\).
- By Vieta's formulas, we know:
- Sum of roots: \(\alpha + \beta = -p\)
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