If the roots of `x^2-b x+c=0` are two consecutive integers, then `b^2-4c` is `0` (b) `1` (c) `2` (d) none of these

Explanation

To solve the problem, we start with the quadratic equation given by:

\[ x^2 - bx + c = 0 \]

where the roots are two consecutive integers. Let's denote these roots as \( \alpha \) and \( \alpha + 1 \).

### Step 1: Use the properties of roots
From Vieta's formulas, we know that:
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