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sin^2pi/6+cos^2pi/3-tan^2pi/4=-1/2...

`sin^2``pi/6``+cos^2``pi/3``-tan^2``pi/4=-1/2`

Text Solution

Verified by Experts

`L.H.S. = sin^2(pi/6)+cos^2(pi/3) - tan^2(pi/4)`
`=(1/2)^2+(1/2)^2 - (1)^2 = 1/4+1/4 - 1 `
`= 1/2-1 = -1/2 = R.H.S`
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