If the middle term in the binomial expansion of `(1/x+xsinx^(10))` is equal to `(63)/8,` find the value of `xdot`

Explanation

`(1/x+xsinx)^10`

Middle term in the above expansion `= 10/2 +1 = 6`

Then,

`T_6 = C(10,5)(1/x)^5(xsinx)^5`

`=> 63/8 = (10*9*8*7*6)/(5*4*3*2*1)sin^5x`

`=>1/8 = 4sin^5x`

`=>sin^5x = 1/32`

`=>sinx = 1/2`

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