[" The ends of the latus rectum "],[" of the parabola (x- "],[" 2) "^(2)=-6(y+1)" are "]

Find the latus rectum of the parabola (y-3)^2=6(x-2)

The length of the latus rectum of the parabola (x+2) ^(2) = - 14 (y-5) is

The ends of the latus rectum of the parabola x^(2)+10x-16y+25=0 are

The end points of the latus rectum of the parabola x ^(2) + 5y =0 is

The end points of the latus rectum of the parabola x ^(2) + 5y =0 is

The equation of the latus rectum of the parabola (y-2)^(2)=-4(x+2) is

The latus rectum of the parabola y^2=-8x is 2.

The ends of latus rectum of parabola x^(2)+8y=0 are

The coordinates of one of the end-points of the latus rectum of the parabola (y - 1)^(2) = 2(x + 2 ) are _