It `n` is a positive integer, prove that `3^(3n)-26n-1` is divisible by `676.`

Explanation

We will prove it using mathematical induction.


Given expression is.

`3^(3n)-26n-1`

When `n = 1`, given expression is,

`3^3-26-1 = 27-27 = 0`

So, for `n=1`, given expession is divisible by `676`.

Let for any `k in N`, given expression is divisible by `676`.

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